(x^2+13x+40)-(x^2+3x)=40

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Solution for (x^2+13x+40)-(x^2+3x)=40 equation: 


Simplifying
(x2 + 13x + 40) + -1(x2 + 3x) = 40

Reorder the terms:
(40 + 13x + x2) + -1(x2 + 3x) = 40

Remove parenthesis around (40 + 13x + x2)
40 + 13x + x2 + -1(x2 + 3x) = 40

Reorder the terms:
40 + 13x + x2 + -1(3x + x2) = 40
40 + 13x + x2 + (3x * -1 + x2 * -1) = 40
40 + 13x + x2 + (-3x + -1x2) = 40

Reorder the terms:
40 + 13x + -3x + x2 + -1x2 = 40

Combine like terms: 13x + -3x = 10x
40 + 10x + x2 + -1x2 = 40

Combine like terms: x2 + -1x2 = 0
40 + 10x + 0 = 40
40 + 10x = 40

Add '-40' to each side of the equation.
40 + -40 + 10x = 40 + -40

Combine like terms: 40 + -40 = 0
0 + 10x = 40 + -40
10x = 40 + -40

Combine like terms: 40 + -40 = 0
10x = 0

Solving
10x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '10'.
x = 0.0

Simplifying
x = 0.0

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